16x^2+70x-2100=0

Solution for 16x^2+70x-2100=0 equation:

16x^2+70x-2100=0

a = 16; b = 70; c = -2100;
Δ = b2-4ac
Δ = 702-4·16·(-2100)
Δ = 139300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{139300}=\sqrt{100*1393}=\sqrt{100}*\sqrt{1393}=10\sqrt{1393}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-10\sqrt{1393}}{2*16}=\frac{-70-10\sqrt{1393}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+10\sqrt{1393}}{2*16}=\frac{-70+10\sqrt{1393}}{32}
$